Frobenius elements #
In algebraic number theory, if L/K is a finite Galois extension of number fields, with rings of
integers 𝓞L/𝓞K, and if q is prime ideal of 𝓞L lying over a prime ideal p of 𝓞K, then
there exists a Frobenius element Frob p in Gal(L/K) with the property that
Frob p x ≡ x ^ #(𝓞K/p) (mod q) for all x ∈ 𝓞L.
Following RingTheory/Invariant.lean, we develop the theory in the setting that
there is a finite group G acting on a ring S, and R is the fixed subring of S.
Main results #
Let S/R be an extension of rings, Q be a prime of S,
and P := R ∩ Q with finite residue field of cardinality q.
AlgHom.IsArithFrobAt: We say that aφ : S →ₐ[R] Sis an (arithmetic) Frobenius atQifφ x ≡ x ^ q (mod Q)for allx : S.AlgHom.IsArithFrobAt.apply_of_pow_eq_one: SupposeSis a domain andφis a Frobenius atQ, thenφ ζ = ζ ^ qfor anym-th root of unityζwithq ∤ m.AlgHom.IsArithFrobAt.eq_of_isUnramifiedAt: SupposeSis noetherian,Qcontains all zero-divisors, and the extension is unramified atQ. Then the Frobenius is unique (if exists).
Let G be a finite group acting on a ring S, and R is the fixed subring of S.
IsArithFrobAt: We say that aσ : Gis an (arithmetic) Frobenius atQifσ • x ≡ x ^ q (mod Q)for allx : S.IsArithFrobAt.mul_inv_mem_inertia: Two Frobenius elements atQdiffer by an element in the inertia subgroup ofQ.IsArithFrobAt.conj: Ifσis a Frobenius atQ, thenτστ⁻¹is a Frobenius atσ • Q.IsArithFrobAt.exists_of_isInvariant: Frobenius element exists.
Let G be a finite group acting on S, and R be the fixed subring.
If Q is a prime of S with finite residue field,
then there exists a Frobenius element σ : G at Q.
Let G be a finite group acting on S, R be the fixed subring, and Q be a prime of S
with finite residue field. This is an arbitrary choice of a Frobenius over Q. It is chosen so that
the Frobenius elements of Q₁ and Q₂ are conjugate if they lie over the same prime.
Equations
- arithFrobAt' R G Q = ⋯.choose ⟨Q, ⋯⟩