Frobenius elements #
In algebraic number theory, if L/K
is a finite Galois extension of number fields, with rings of
integers 𝓞L/𝓞K
, and if q
is prime ideal of 𝓞L
lying over a prime ideal p
of 𝓞K
, then
there exists a Frobenius element Frob p
in Gal(L/K)
with the property that
Frob p x ≡ x ^ #(𝓞K/p) (mod q)
for all x ∈ 𝓞L
.
Following RingTheory/Invariant.lean
, we develop the theory in the setting that
there is a finite group G
acting on a ring S
, and R
is the fixed subring of S
.
Main results #
Let S/R
be an extension of rings, Q
be a prime of S
,
and P := R ∩ Q
with finite residue field of cardinality q
.
AlgHom.IsArithFrobAt
: We say that aφ : S →ₐ[R] S
is an (arithmetic) Frobenius atQ
ifφ x ≡ x ^ q (mod Q)
for allx : S
.AlgHom.IsArithFrobAt.apply_of_pow_eq_one
: SupposeS
is a domain andφ
is a Frobenius atQ
, thenφ ζ = ζ ^ q
for anym
-th root of unityζ
withq ∤ m
.AlgHom.IsArithFrobAt.eq_of_isUnramifiedAt
: SupposeS
is noetherian,Q
contains all zero-divisors, and the extension is unramified atQ
. Then the Frobenius is unique (if exists).
Let G
be a finite group acting on a ring S
, and R
is the fixed subring of S
.
IsArithFrobAt
: We say that aσ : G
is an (arithmetic) Frobenius atQ
ifσ • x ≡ x ^ q (mod Q)
for allx : S
.IsArithFrobAt.mul_inv_mem_inertia
: Two Frobenius elements atQ
differ by an element in the inertia subgroup ofQ
.IsArithFrobAt.conj
: Ifσ
is a Frobenius atQ
, thenτστ⁻¹
is a Frobenius atσ • Q
.IsArithFrobAt.exists_of_isInvariant
: Frobenius element exists.
Let G
be a finite group acting on S
, and R
be the fixed subring.
If Q
is a prime of S
with finite residue field,
then there exists a Frobenius element σ : G
at Q
.
Let G
be a finite group acting on S
, R
be the fixed subring, and Q
be a prime of S
with finite residue field. This is an arbitrary choice of a Frobenius over Q
. It is chosen so that
the Frobenius elements of Q₁
and Q₂
are conjugate if they lie over the same prime.
Equations
- arithFrobAt' R G Q = ⋯.choose ⟨Q, ⋯⟩