Infinite sums and products in nonarchimedean abelian groups #
Let G
be a complete nonarchimedean abelian group and let f : α → G
be a function. We prove that
f
is unconditionally summable if and only if f a
tends to zero on the cofinite filter on α
(NonarchimedeanAddGroup.summable_iff_tendsto_cofinite_zero
). We also prove the analogous result in
the multiplicative setting (NonarchimedeanGroup.multipliable_iff_tendsto_cofinite_one
).
We also prove that multiplication distributes over arbitrarily indexed sums in a nonarchimedean
ring. That is, let R
be a nonarchimedean ring, let f : α → R
be a function that sums to a : R
,
and let g : β → R
be a function that sums to b : R
. Then fun (i : α × β) ↦ (f i.1) * (g i.2)
sums to a * b
(HasSum.mul_of_nonarchimedean
).
Let G
be a nonarchimedean multiplicative abelian group, and let f : α → G
be a function that
tends to one on the filter of cofinite sets. For each finite subset of α
, consider the partial
product of f
on that subset. These partial products form a Cauchy filter.
Let G
be a nonarchimedean additive abelian group, and let f : α → G
be a function
that tends to zero on the filter of cofinite sets. For each finite subset of α
, consider the
partial sum of f
on that subset. These partial sums form a Cauchy filter.
Let G
be a complete nonarchimedean multiplicative abelian group, and let f : α → G
be a
function that tends to one on the filter of cofinite sets. Then f
is unconditionally
multipliable.
Let G
be a complete nonarchimedean additive abelian group, and let f : α → G
be a
function that tends to zero on the filter of cofinite sets. Then f
is unconditionally summable.
Let G
be a complete nonarchimedean multiplicative abelian group. Then a function f : α → G
is unconditionally multipliable if and only if it tends to one on the filter of cofinite sets.
Let G
be a complete nonarchimedean additive abelian group. Then a function
f : α → G
is unconditionally summable if and only if it tends to zero on the filter of cofinite
sets.
Let R
be a nonarchimedean ring, let f : α → R
be a function that sums to a : R
,
and let g : β → R
be a function that sums to b : R
. Then fun i : α × β ↦ f i.1 * g i.2
sums to a * b
.
Let R
be a nonarchimedean ring. If functions f : α → R
and g : β → R
are summable, then
so is fun i : α × β ↦ f i.1 * g i.2
.