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Mathlib.LinearAlgebra.Basis.Fin

Bases indexed by Fin #

noncomputable def Module.Basis.mkFinCons {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N : Submodule R M} (y : M) (b : Basis (Fin n) R N) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : ∀ (z : M), ∃ (c : R), z + c y N) :
Basis (Fin (n + 1)) R M

Let b be a basis for a submodule N of M. If y : M is linear independent of N and y and N together span the whole of M, then there is a basis for M whose basis vectors are given by Fin.cons y b.

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    @[simp]
    theorem Module.Basis.coe_mkFinCons {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N : Submodule R M} (y : M) (b : Basis (Fin n) R N) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : ∀ (z : M), ∃ (c : R), z + c y N) :
    (mkFinCons y b hli hsp) = Fin.cons y (Subtype.val b)
    noncomputable def Module.Basis.mkFinConsOfLE {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N O : Submodule R M} (y : M) (yO : y O) (b : Basis (Fin n) R N) (hNO : N O) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : zO, ∃ (c : R), z + c y N) :
    Basis (Fin (n + 1)) R O

    Let b be a basis for a submodule N ≤ O. If y ∈ O is linear independent of N and y and N together span the whole of O, then there is a basis for O whose basis vectors are given by Fin.cons y b.

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      @[simp]
      theorem Module.Basis.coe_mkFinConsOfLE {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N O : Submodule R M} (y : M) (yO : y O) (b : Basis (Fin n) R N) (hNO : N O) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : zO, ∃ (c : R), z + c y N) :
      (mkFinConsOfLE y yO b hNO hli hsp) = Fin.cons y, yO ((Submodule.inclusion hNO) b)
      noncomputable def Module.Basis.mkFinSnoc {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N : Submodule R M} (b : Basis (Fin n) R N) (y : M) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : ∀ (z : M), ∃ (c : R), z + c y N) :
      Basis (Fin (n + 1)) R M

      Let b be a basis for a submodule N of M. If y : M is linear independent of N and y and N together span the whole of M, then there is a basis for M whose basis vectors are given by Fin.snoc b y.

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        @[simp]
        theorem Module.Basis.coe_mkFinSnoc {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N : Submodule R M} (b : Basis (Fin n) R N) (y : M) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : ∀ (z : M), ∃ (c : R), z + c y N) :
        (b.mkFinSnoc y hli hsp) = Fin.snoc (Subtype.val b) y
        noncomputable def Module.Basis.mkFinSnocOfLE {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N O : Submodule R M} (b : Basis (Fin n) R N) (hNO : N O) (y : M) (yO : y O) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : zO, ∃ (c : R), z + c y N) :
        Basis (Fin (n + 1)) R O

        Let b be a basis for a submodule N ≤ O. If y ∈ O is linear independent of N and y and N together span the whole of O, then there is a basis for O whose basis vectors are given by Fin.snoc b y.

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          @[simp]
          theorem Module.Basis.coe_mkFinSnocOfLE {R : Type u_3} {M : Type u_5} [Ring R] [AddCommGroup M] [Module R M] {n : } {N O : Submodule R M} (b : Basis (Fin n) R N) (hNO : N O) (y : M) (yO : y O) (hli : ∀ (c : R), xN, c y + x = 0c = 0) (hsp : zO, ∃ (c : R), z + c y N) :
          (b.mkFinSnocOfLE hNO y yO hli hsp) = Fin.snoc ((Submodule.inclusion hNO) b) y, yO
          noncomputable def Module.Basis.finTwoProd (R : Type u_7) [Semiring R] :
          Basis (Fin 2) R (R × R)

          The basis of R × R given by the two vectors (1, 0) and (0, 1).

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            @[simp]
            @[simp]
            @[simp]
            theorem Module.Basis.coe_finTwoProd_repr {R : Type u_7} [Semiring R] (x : R × R) :
            ((Basis.finTwoProd R).repr x) = ![x.1, x.2]