SeminormFromConst #
In this file, we prove [BGR, Proposition 1.3.2/2][bosch-guntzer-remmert] : starting from a
power-multiplicative seminorm on a commutative ring R
and a nonzero c : R
, we create a new
power-multiplicative seminorm for which c
is multiplicative.
Main Definitions #
seminormFromConst'
: the real-valued function sendingx ∈ R
to the limit of(f (x * c^n))/((f c)^n)
.seminormFromConst
: the functionseminormFromConst'
as aRingSeminorm
onR
.
Main Results #
seminormFromConst_isNonarchimedean
: the functionseminormFromConst' hf1 hc hpm
is nonarchimedean when f is nonarchimedean.seminormFromConst_isPowMul
: the functionseminormFromConst' hf1 hc hpm
is power-multiplicative.seminormFromConst_const_mul
: for everyx : R
,seminormFromConst' hf1 hc hpm (c * x)
equals the productseminormFromConst' hf1 hc hpm c * SeminormFromConst' hf1 hc hpm x
.
References #
- [S. Bosch, U. Güntzer, R. Remmert, Non-Archimedean Analysis][bosch-guntzer-remmert]
Tags #
SeminormFromConst, Seminorm, Nonarchimedean
For a ring seminorm f
on R
and c ∈ R
, the sequence given by (f (x * c^n))/((f c)^n)
.
Instances For
The terms in the sequence seminormFromConst_seq c f x
are nonnegative.
The image of seminormFromConst_seq c f x
is bounded below by zero.
seminormFromConst_seq c f 0
is the constant sequence zero.
If 1 ≤ n
, then seminormFromConst_seq c f 1 n = 1
.
seminormFromConst_seq c f x
is antitone.
The real-valued function sending x ∈ R
to the limit of (f (x * c^n))/((f c)^n)
.
Equations
- seminormFromConst' hf1 hc hpm x = ⋯.choose
Instances For
We prove that seminormFromConst' hf1 hc hpm x
is the limit of the sequence
seminormFromConst_seq c f x
as n
tends to infinity.
seminormFromConst' hf1 hc hpm 1 = 1
.
The function seminormFromConst
is a RingSeminorm
on R
.
Equations
- seminormFromConst hf1 hc hpm = { toFun := seminormFromConst' hf1 hc hpm, map_zero' := ⋯, add_le' := ⋯, neg' := ⋯, mul_le' := ⋯ }
Instances For
seminormFromConst' hf1 hc hpm 1 ≤ 1
.
The function seminormFromConst' hf1 hc hpm
is nonarchimedean.
The function seminormFromConst' hf1 hc hpm
is power-multiplicative.
The function seminormFromConst' hf1 hc hpm
is bounded above by x
.
If x : R
is multiplicative for f
, then seminormFromConst' hf1 hc hpm x = f x
.
If x : R
is multiplicative for f
, then it is multiplicative for
seminormFromConst' hf1 hc hpm
.
seminormFromConst' hf1 hc hpm c = f c
.
For every x : R
, seminormFromConst' hf1 hc hpm (c * x)
equals the product
seminormFromConst' hf1 hc hpm c * SeminormFromConst' hf1 hc hpm x
.
If K
is a field, the function seminormFromConst
is a RingNorm
on K
.
Equations
- normFromConst hg1 hg_k hg_pm = (seminormFromConst hg1 hg_k hg_pm).toRingNorm ⋯