Joint eigenspaces of a commuting pair of symmetric operators #
This file collects various decomposition results for joint eigenspaces of a commuting pair of symmetric operators on a finite-dimensional inner product space.
Main Result #
LinearMap.IsSymmetric.directSum_isInternal_of_commute
establishes that if{A B : E โโ[๐] E}
, thenIsSymmetric A
,IsSymmetric B
andA โโ B = B โโ A
imply thatE
decomposes as an internal direct sum of the pairwise orthogonal spaceseigenspace B ฮผ โ eigenspace A ฮฝ
TODO #
Develop a Diagonalization
structure for linear maps and / or matrices which consists of a basis,
and a proof obligation that the basis vectors are eigenvectors.
Tags #
self-adjoint operator, simultaneous eigenspaces, joint eigenspaces
If a pair of operators commute, then the eigenspaces of one are invariant under the other.
The simultaneous eigenspaces of a pair of commuting symmetric operators form an
OrthogonalFamily
.
The intersection of eigenspaces of commuting selfadjoint operators is equal to the eigenspace of one operator restricted to the eigenspace of the other, which is an invariant subspace because the operators commute.
If A and B are commuting symmetric operators on a finite dimensional inner product space then the eigenspaces of the restriction of B to any eigenspace of A exhaust that eigenspace.
If A and B are commuting symmetric operators acting on a finite dimensional inner product space, then the simultaneous eigenspaces of A and B exhaust the space.
Given a commuting pair of symmetric linear operators on a finite dimensional inner product space, the space decomposes as an internal direct sum of simultaneous eigenspaces of these operators.