Fourier inversion formula #
In a finite-dimensional real inner product space, we show the Fourier inversion formula, i.e.,
πβ» (π f) v = f v
if f
and π f
are integrable, and f
is continuous at v
. This is proved
in MeasureTheory.Integrable.fourier_inversion
. See also Continuous.fourier_inversion
giving πβ» (π f) = f
under an additional continuity assumption for f
.
We use the following proof. A naΓ―ve computation gives
πβ» (π f) v = β«_w exp (2 I Ο βͺw, vβ«) π f (w) dw = β«_w exp (2 I Ο βͺw, vβ«) β«_x, exp (-2 I Ο βͺw, xβ«) f x dx) dw = β«_x (β«_ w, exp (2 I Ο βͺw, v - xβ« dw) f x dx
However, the Fubini step does not make sense for lack of integrability, and the middle integral
β«_ w, exp (2 I Ο βͺw, v - xβ« dw
(which one would like to be a Dirac at v - x
) is not defined.
To gain integrability, one multiplies with a Gaussian function exp (-cβ»ΒΉ βwβ^2)
, with a large
(but finite) c
. As this function converges pointwise to 1
when c β β
, we get
β«_w exp (2 I Ο βͺw, vβ«) π f (w) dw = lim_c β«_w exp (-cβ»ΒΉ βwβ^2 + 2 I Ο βͺw, vβ«) π f (w) dw
.
One can perform Fubini on the right hand side for fixed c
, writing the integral as
β«_x (β«_w exp (-cβ»ΒΉβwβ^2 + 2 I Ο βͺw, v - xβ« dw)) f x dx
.
The middle factor is the Fourier transform of a more and more flat function
(converging to the constant 1
), hence it becomes more and more concentrated, around the
point v
. (Morally, it converges to the Dirac at v
). Moreover, it has integral one.
Therefore, multiplying by f
and integrating, one gets a term converging to f v
as c β β
.
Since it also converges to πβ» (π f) v
, this proves the result.
To check the concentration property of the middle factor and the fact that it has integral one, we rely on the explicit computation of the Fourier transform of Gaussians.
Fourier inversion formula: If a function f
on a finite-dimensional real inner product
space is integrable, and its Fourier transform π f
is also integrable, then πβ» (π f) = f
at
continuity points of f
.
Fourier inversion formula: If a function f
on a finite-dimensional real inner product
space is continuous, integrable, and its Fourier transform π f
is also integrable,
then πβ» (π f) = f
.
Fourier inversion formula: If a function f
on a finite-dimensional real inner product
space is integrable, and its Fourier transform π f
is also integrable, then π (πβ» f) = f
at
continuity points of f
.
Fourier inversion formula: If a function f
on a finite-dimensional real inner product
space is continuous, integrable, and its Fourier transform π f
is also integrable,
then π (πβ» f) = f
.